SOLUTION: Suppose that Maria has 160 coins consisting of pennies, nickels, and dimes. The number of nickels she has is 5 less than twice the number of pennies; the number of dimes she has i
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Question 500170: Suppose that Maria has 160 coins consisting of pennies, nickels, and dimes. The number of nickels she has is 5 less than twice the number of pennies; the number of dimes she has is 21 less than three times the number of pennies. How many coins of each kind does she have? Answer by mananth(16946) (Show Source):
You can put this solution on YOUR website! pennies x
nickels ( 2 x -5 )
dimes ( 3 x -21 )
x+2x-5+3x-21=160
6x-26=160
+26
6x=160+26
6x=186
/6
x=31
pennies = 31
nickels ==> 2x-5 =>2*31-5=57
Dimes==>3x-21==>3*31-21=72
CHECK
31+57+72=160
