SOLUTION: In addition to finding unions and intersections of intervals, it is possible to apply other operations to intervals. For instance, (-1,2)^2 is the interval that results from square

In addition to finding unions and intersections of intervals, it is possible
to apply other operations to intervals. For instance, (-1,2)^2 is the interval
that results from squareing every number in the interval (-1,2). This gives
[1,4). Thus (-1,2)^2 = [1,4).

Hey, that's wrong!!!!! It should be [0,4), 

That's because smallest number in (-1,2)² is 0² and the largest number
is just less than but not including (2)² = 4.  So that's the interval [0,4)

a. Find (-4,2)^2

The smallest number is 0² and the largest number is just less than
but not including (-4)² = 16

So that's the interval [0,16)

--------------------------------

b. Find 1/[-2,3], the reciprocal of every number in [-2,3].

The smallest number is 1/(-2) = -1/2 and the largest number is 1/3. Both
are included.  However there is no number whose reciprocal is 0, so we
must rule out 0.

So that's the interval [-1/2, 0) U (0, 1/3] 

-------------------------------

c. Find ABS(-4,5), the absolute value of every number in (-4,5)

The smallest number is ABS(0) = 0 and the largest number is just less
than but not including ABS(5) = 5.

So that's [0,5)

Edwin