SOLUTION: Hi, Can you please help me solve this problem? 7/2x (seven over two X)+ 1/3(one over three)=1/x (one over x)+7/6(seven over six) I have tried solving it, but i cant even get pas

Algebra ->  Problems-with-consecutive-odd-even-integers -> SOLUTION: Hi, Can you please help me solve this problem? 7/2x (seven over two X)+ 1/3(one over three)=1/x (one over x)+7/6(seven over six) I have tried solving it, but i cant even get pas      Log On


   

Question 499658: Hi, Can you please help me solve this problem?
7/2x (seven over two X)+ 1/3(one over three)=1/x (one over x)+7/6(seven over six)
I have tried solving it, but i cant even get past the first step.
Thank you
Answer by Earlsdon(6294) About Me  (Show Source):
You can put this solution on YOUR website!
Solve for x:
7%2F2x+%2B+1%2F3+=+1%2Fx%2B7%2F6 Add the fractions by finding the LCDs.
3%2A7%2F%283%2A2x%29+%2B+1%2A2x%2F%283%2A2x%29+=+6%2A1%2F%286%2Ax%29+%2B+7%2Ax%2F%286%2Ax%29 Simplify.
%2821%2B2x%29%2F6x+=+%286%2B7x%29%2F6x Multiply both sides by 6x.
21%2B2x+=+6%2B7x Subtact 2x from both sides.
21+=+6%2B5x Subtract 6 from both sides.
15+=+5x Divide both sides by 5.
3+=+x
highlight%28x+=+3%29