SOLUTION: a collection of dimes and quarters is worth $25. there are 40 more dimes than quarters. how many of each are there?

Algebra ->  Systems-of-equations -> SOLUTION: a collection of dimes and quarters is worth $25. there are 40 more dimes than quarters. how many of each are there?      Log On


   

Question 4996: a collection of dimes and quarters is worth $25. there are 40 more dimes than quarters. how many of each are there?
Answer by rapaljer(4671) About Me  (Show Source):
You can put this solution on YOUR website!
Let x = number of quarters
x+ 40 = number of dimes

Working the problem in "cents", you must change the $25.00 to 2500 cents.
25(x) + 10(x+ 40) = 2500
25x + 10x + 400 = 2500
35x + 400 - 400 = 2500 - 400
35x = 2100

+%2835x%29%2F35+=+2100%2F35+
+x=+2100%2F35+=+60 quarters
x+40 = 100 dimes

Check: Total value equals $25.
Quarters = .25(60) = $15
Dimes = .10 (100) = $10
Total = $25

R^2 at SCC