SOLUTION: {{{ sqrt( x+1 ) }}}= {{{ sqrt( x+6 ) }}} -1

Algebra ->  Square-cubic-other-roots -> SOLUTION: {{{ sqrt( x+1 ) }}}= {{{ sqrt( x+6 ) }}} -1      Log On


   

Question 49955: +sqrt%28+x%2B1+%29+= +sqrt%28+x%2B6+%29+ -1
Answer by Earlsdon(6294) About Me  (Show Source):
You can put this solution on YOUR website!
Solve:
sqrt%28x%2B1%29+=+sqrt%28x%2B6%29-1 First, square both sides.
x%2B1+=+%28x%2B6%29-2sqrt%28x%2B6%29%2B1 Simplify.
x%2B1+=+%28x%2B1%29%2B6-2sqrt%28x%2B6%29 Subtract (x+1) from both sides.
0+=+6-2sqrt%28x%2B6%29 Add 2sqrt%28x%2B6%29 to both sides.
2sqrt%28x%2B6%29+=+6 Divide both sides by 2.
sqrt%28x%2B6%29+=+3 Now square both sides.
x%2B6+=+9 Finally, subtract 6 from both sides.
x+=+3
Check:
sqrt%283%2B1%29+=+sqrt%283%2B6%29-1
sqrt%284%29+=+sqrt%289%29-1
2+=+3-1
2+=+2