SOLUTION: Find the center and radius of the circle whose equation is 4x^2+x+4y^2-6y-15=0.

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Question 499384: Find the center and radius of the circle whose equation is 4x^2+x+4y^2-6y-15=0.
Answer by Alan3354(69443) About Me  (Show Source):
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Find the center and radius of the circle whose equation is 4x^2+x+4y^2-6y-15=0
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4x^2+x+4y^2-6y-15=0
4x^2+x+4y^2-6y = 15
Complete the squares
x^2+x/4 + y^2- 3y/2 = 15/4
x^2+x/4 + 1/64 + y^2- 3y/2 + 9/16 = 15/4 + 1/64 + 9/16
%28x+%2B+1%2F8%29%5E2+%2B+%28y+-+3%2F4%29%5E2+=+277%2F64
Center at (-1/8,3/4)
radius+=+sqrt%28277%29%2F8