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Question 499310: 7x=3y+7and 5y=6x+11
Answer by oberobic(2304)   (Show Source):
You can put this solution on YOUR website! EQ1. 7x - 3y = 7
EQ2. 6x - 5y = -11
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Multiply EQ1 by 5 and EQ2 by 3
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35x - 15y = 35
18x - 15y = -33
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Subtract EQ2 from EQ1
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17x = 68
x = 4
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Substitute x=4 into EQ1
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7x -3y = 7
28 -3y = 7
-3y = -21
y = 7
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Always check your work.
Substitute these values into EQ2.
(You cannot use EQ1 again.)
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5y = 35
6x = 24
6x+11 = 35
5y = 6x+11 true
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Answer:
x = 4
y = 7
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Done.
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