SOLUTION: b) Find the point on the x-axis which is equidistant from (3, 2) and (− 5,− 20)

Algebra ->  Length-and-distance -> SOLUTION: b) Find the point on the x-axis which is equidistant from (3, 2) and (− 5,− 20)      Log On


   

Question 499282: b) Find the point on the x-axis which is equidistant from (3, 2) and (− 5,− 20)
Answer by chessace(471) About Me  (Show Source):
You can put this solution on YOUR website!
By Pythag, Dist=sqrt((x-3)^2 + 2^2)) = sqrt((x+5)^2 + 20^2)
square both: x^2-6x+9 + 4 = x^2+10x+25 + 400
-16x = 400+25 - 13 = 412
x = -25.75
Point is at (-25.75, 0)