SOLUTION: Graph: y = 2x^2 - 4x

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Question 49923: Graph: y = 2x^2 - 4x
Answer by rapaljer(4671) About Me  (Show Source):
You can put this solution on YOUR website!
The vertex for y = ax^2 + bx +c will always be at x=%28-b%29%2F%282a%29+

In this case a=2 and b = -4, so vertex is at x=4%2F%282%2A2%29=1

If x = 1, then find the y coordinate by substituting x= 1 into the equation for y, y = 2*1^2 - 4*1 = -2.

This is a parabola that opens upward with vertex at (1,-2). It should look like this:
graph+%28300%2C300%2C-6%2C6%2C-6%2C6%2C+2x%5E2-4x%29+

R^2 at SCC