SOLUTION: write the equation of the line that contains the x-intercept of 2x+3y=-(x+2y)-12 and the y-intercept of 2/3(2x+3y)=6.

Algebra ->  Linear-equations -> SOLUTION: write the equation of the line that contains the x-intercept of 2x+3y=-(x+2y)-12 and the y-intercept of 2/3(2x+3y)=6.      Log On


   

Question 499227: write the equation of the line that contains the x-intercept of 2x+3y=-(x+2y)-12 and the y-intercept of 2/3(2x+3y)=6.
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
write the equation of the line that contains the
:
x-intercept of 2x+3y=-(x+2y)-12
x intercept occurs when y = 0 therefore we have
2x + 3(0) = -(x + 2(0)) - 12
2x = -x - 12
2x + x = -12
3x = -12
x = -4 is the x intercept
:
the y-intercept of 2/3(2x+3y)=6
y intercept occurs when x = 0 therfore
%282%2F3%29+%282%280%29%2B3y%29= 6
%282%2F3%29+%283y%29= 6
cancel 3
2y = 6
y = 3 is the y intercept
:
Write the slope intercept form y = mx + b, with these values we have
y = mx + 3
Find m using the x intercept (y=0)
-4m + 3 = 0
-4m = -3
m = %28-3%29%2F%28-4%29
m = 3%2F4
therefore
y = 3%2F4x + 3 is the equation