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Question 49918: Simplifying a product of radical expressions.
(2 square root of 3-3 square root of 10) (6 square root 10-3 square root of 3)
3x+3x+9xyz=z
Answer by ilana(307)   (Show Source):
You can put this solution on YOUR website! I am going to use the notation "rt" for "square root of", so the problem is (2rt3-3rt10)(6rt10-3rt3). Now, we use the FOIL method, or any method of multiplying binomials. If it is confusing for you to use radicals, you can pretend the rt3 and rt10 are variables, like x and y. So you get 12rt3rt10 - 6rt3rt3 - 18rt10rt10 + 9rt10rt3. rt3rt10 = rt10rt3 = rt30, rt3rt3=3, and rt10rt10=10, so we get 12rt30-18-180+9rt30, so the final answer is 21rt30-198.
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