SOLUTION: Of a journey, 4/5 of the distance was covered on a plane and 1/6 by driving. If, for the rest of the trip, 5 miles is spent walking, how many miles was the total property?

Algebra ->  Percentage-and-ratio-word-problems -> SOLUTION: Of a journey, 4/5 of the distance was covered on a plane and 1/6 by driving. If, for the rest of the trip, 5 miles is spent walking, how many miles was the total property?      Log On


   



Question 498935: Of a journey, 4/5 of the distance was covered on a plane and 1/6 by driving. If, for the rest of the trip, 5 miles is spent walking, how many miles was the total property?
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
Of a journey, 4/5 of the distance was covered on a plane and 1/6 by driving.
If, for the rest of the trip, 5 miles is spent walking, how many miles was the total property?
:
Let x = the total distance of the journey
:
total dist - plane dist - drive dist = 5 miles
x - 4%2F5x - 1%2F6x = 5
:
get rid of those annoying fractions, multiply by 30, results
30x - 6(4)x - 5x = 30(5)
:
30x - 24x - 5x = 150
30x - 29x = 150
x = 150 mi is the total dist
:
:
You can confirm this, calculate:
150 - 4%2F5(150) - 1%2F6(150) =