SOLUTION: Okay, the gist of the math problem is.. A farmer wants to mix a bag containing 50% corn and another bag containing 90% corn to get a 30 lbs bag containing 80% corn.
What I have
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-> SOLUTION: Okay, the gist of the math problem is.. A farmer wants to mix a bag containing 50% corn and another bag containing 90% corn to get a 30 lbs bag containing 80% corn.
What I have
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Question 498898: Okay, the gist of the math problem is.. A farmer wants to mix a bag containing 50% corn and another bag containing 90% corn to get a 30 lbs bag containing 80% corn.
What I have so far for the equation is.. 0.50x + 0.90x = ???
I don't know how to 'plug-in' the other 0.80 and the weight of the bag.
I hope this makes sense!! Thank you!! Answer by Earlsdon(6294) (Show Source):
You can put this solution on YOUR website! Try this!
Let x = the number of pounds of the 50% corn. Then the number of pounds of the 90% corn required to make 30 pounds of 80% corn will be (30-x) and, when added together (x+(30-x) = 30) you will get 30 pounds of corn. So we can write an equation to solve for x:
0.5x+0.9(30-x) = 0.8(30) Simplify and solve for x.
0.5x+27-0.9x = 24
-0.4x+27 = 24
-0.4x = -3
x = 7.5
The farmer will need to mix 7.5 pounds of the 50% corn with (30-7.5 = 22.5)pounds of the 90% corn to obtain 30 pounds of 80% corn.
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