SOLUTION: paul and frank are on the same path 39.15 miles apart. they are going to ride their bike towards each other until they meet. frank starts pedaling 1.5 hours before paul. paul rides
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Question 498819: paul and frank are on the same path 39.15 miles apart. they are going to ride their bike towards each other until they meet. frank starts pedaling 1.5 hours before paul. paul rides 1.8 miles per hour faster than frank. if they meet 3 hours after paul starts riding, find the speed of each biker. Answer by mananth(16946) (Show Source):
You can put this solution on YOUR website! paul and frank are on the same path 39.15 miles apart. they are going to ride their bike towards each other until they meet. frank starts pedaling 1.5 hours before paul. paul rides 1.8 miles per hour faster than frank. if they meet 3 hours after paul starts riding, find the speed of each biker.
Frank speed = x mph
Paul speed = x+1.8 mph
Frank leaves 1.5 hours early
distance traveled by Frank in in 1.5 hours = 1.5x
so when Paul starts Frank is (39.15-1.5x) miles away
they are pedalling towards each other
so add up the speeds
2x+1.8
t= d/r
t= 3 hours
d= (39.15-1.5x)
r= 2x+1.8
3= (39.15-1.5x)/(2x+1.8)
6x+5.4 = 39.15-1.5x
7.5x=39.15-5.4
7.5x=33.75
x=4.5
Frank Speed = 4.5 mph
Paul speed = 6.3 mph
m.ananth@hotmail.ca
