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Question 498552: how do i graph the line passing through (2,4) that is parallel to the graph of x-3y=6
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! how do i graph the line passing through (2,4) that is parallel to the graph of x-3y=6
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Find the slope of x-3y=6
3y = x-6
y = (1/3)x-2
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slope = 1/3
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Find equation of line with slope = 1/3 passing thru (2,4)
Form: y = mx + b
Solve for "b":
4 = (1/3)2 + b
12/3 = 2/3 + b
10/3 = b
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Equation:
y = (1/3)x + (10/3)
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Cheers,
Stan H.
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