Question 49840: Determine which two equations represent perpendicular lines.
y=4/7x-3
y=3x-4/7
y=-1/3x + 4/7
y=1/3x-3 4/7
Answer by rapaljer(4671)   (Show Source):
You can put this solution on YOUR website! When two lines are perpendicular, the slope of one line is the negative reciprocal of the slope of the other line. Also, since the given lines are in slope intercept form, the coefficient of x is the slope. If the equation of the line is y=mx+b, then the slope is m.
Therefore the slopes of the given lines are as follows:
y=4/7x-3 -------> m=4/7
y=3x-4/7 -------> m=3
y=-1/3x + 4/7 --> m=-1/3
y=1/3x-3 4/7 ---> m=1/3
Of the given slopes, which two are such that one is the negative reciprocal of the other? Answer: m= 3 and m= -1/3.
Therefore, the second and third lines are perpendicular.
y=3x-4/7
y=-1/3x + 4/7
R^2 at SCC
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