SOLUTION: Can anyone Please help me, this problem is confusing to me graph the function find the vertex line of symmetry and maximum or minimum value f(x)=(x+3)^2 -2 the vertex is

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Question 498398: Can anyone Please help me, this problem is confusing to me
graph the function find the vertex line of symmetry and maximum or minimum value
f(x)=(x+3)^2 -2
the vertex is
the minimum value is f(x)=

the answer i got was
(-3,-2)
the second part f(x)=-2

Answer by Theo(13342) (Show Source):
You can put this solution on YOUR website!
equation is f(x) = (x+3)^2 - 2
here's the graph

the vertex is at (-3,-2)
the minimum point is at the vertex, so the minimum point is at (-3,-2)
the line of symmetry is at x = -3
the line of symmetry for this graph is a vertical line that passes through the vertex.
the equation for that line would be x = -3.
the equation of f(x) = (x+3)^2 - 2 is a quadratic equation.
if you multiply out the factor, you get:
f(x) = x^2 + 6x + 9 - 2 which becomes:
f(x) = x^2 + 6x + 7
set this equation to 0 and you get the standard form of a quadratic equation.
the standard form is:
ax^2 + bx + c = 0
in this equation:
a = 1
b = 6
c = 7
the formula for the vertex is:
x = -b/2a
replace b and a with their values and you get:
x = -6/2 which becomes x = -3
when x = -3, f(-3x) = (-3)^2 + 6(-3) + 7 which becomes f(-3) = 9 - 18 + 7 which becomes f(-3) = -2.
the vertex is at (-3,-2).
that's the same point you got.
here's another picture of the graph for this equation that i could mark up for you.