SOLUTION: The vertices of a triangle are located at X(-2,-1),Y(2,5), and Z(4,3). What is the perimeter of this triangle ?

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Question 498384: The vertices of a triangle are located at X(-2,-1),Y(2,5), and Z(4,3). What is the perimeter of this triangle ?
Answer by cleomenius(959) About Me  (Show Source):
You can put this solution on YOUR website!
You can find the distacce between vertices using the distance formula
sqrt%28%28x2-x1%29%5E2+%2B+%28y2+-+y1%29%5E2%29
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XY = sqrt%28%282-+-2%29%5E2+%2B+%285+-+-+1%29%5E2%29
XY = sqrt%28%284%29%5E2+%2B+%286%29%5E2%29
XY = sqrt%2852%29
XY = 2sqrt%2813%29
==============================================
YZ = sqrt%28%284+-2%29%5E2+%2B+%283+-+5%29%5E2%29
YZ = sqrt%28%282%29%5E2+%2B+%28-2%29%5E2%29
YZ = sqrt%288%29
YZ = 2sqrt%282%29
===============================================
XZ = sqrt%28%284+-+-2%29%5E2+%2B+%283+-+-+1%29%5E2%29
XZ = sqrt%28%286%29%5E2+%2B+%284%29%5E2%29
XZ = sqrt%2852%29
XZ = 2sqrt%2813%29
===============================================
The perimeter would be 4sqrt%2813%29 + 2sqrt%282%29
Cleomenius