SOLUTION: Please solve the equation and check your solution. sqrt of 2y+7+4=y

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Question 49777: Please solve the equation and check your solution.
sqrt of 2y+7+4=y
Answer by tutorcecilia(2152) About Me  (Show Source):
You can put this solution on YOUR website!
%28+%28%28sqrt%282y%2B7%29%29+%2B+4%29%29+=+y%29%29%29%29+
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%28+%28%28sqrt%282y%2B7%29%29+%2B+4+-+4%29%29+=+y+-+4%29%29%29%29+ [Isolate the radical to one side]
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%28+%28%28sqrt%282y%2B7%29%29%29%29+=+y+-+4%29%29%29%29+
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%28+%28%28%28sqrt%282y%2B7%29%29%29%29%29%5E2+=+%28%28y+-+4%29%29%5E2%29%29%29%29+ [Square both sides]
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2y+7 = (y - 4)(y - 4) [Multiply by using the FOIL method]
2y+7=y^2-8y+16[Set the equaion equal to zero by getting all of the terms to one side of the equation]
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2y+7-7=y^2-7-8y+16
2y=y^2-8y+9
2y-2y=y^2-8y-2y+9
0=y^2-10y+9 [Factor]
0 = (y-9)(y-1) [solve for y]
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0=y-9
y=9
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0=y-1
y=1
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y=9 or y=1 [Final answers]
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Check by plugging the values of "y" back into the original equatin.