SOLUTION: Jaidee left the airport driving toward the desert three hours before Wilbur. Wilbur drove in the opposite direction going 18 km/h faster than Jaidee for one hour after which time t

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Question 496648: Jaidee left the airport driving toward the desert three hours before Wilbur. Wilbur drove in the opposite direction going 18 km/h faster than Jaidee for one hour after which time they were 193 km apart. Find Jaidee's speed.
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
You can think of this as one of them traveling
at the sum of their speeds and the other one
standing still.
I'll say Wilbur is standing still and Jaidee is
moving at the sum of their speeds.
If s is Jaidee's speed alone, their sum is
+s+%2B+s+%2B+18+=+2s+%2B+18
Jaidee drove for 3 hrs when Wilbur wasn't driving,
so Jaidee's head start was +d%5B1%5D+=+s%2A3+
+193+ km is their distance apart after +3+%2B+1+=+4+ hrs
+193+=+3s+%2B+%282s+%2B+18%29%2A1+
+193+=+3s+%2B+2s+%2B+18+
+5s+=+193+-+18+
+5s+=+175+
+s+=+35+
+s+%2B+18+=+53+
Jaidee's speed is 35 km/hr
check:
The sum of their speeds is +53+%2B+35+=+88+ km/hr
+193+=+3%2A35+%2B+88+
+193+=+105+%2B+88+
+193+=+193+
OK