SOLUTION: Give the solution of the following system. [y=x^2+4 y-4x=1]

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Question 496178: Give the solution of the following system.
[y=x^2+4
y-4x=1]
Answer by unlockmath(1688) About Me  (Show Source):
You can put this solution on YOUR website!
Hello,
Let's solve this by substituting:
y=x^2+4
y-4x=1
Plug first equation into the second as:
x^2+4-4x=1
rearrange and subtract 1 to get:
x^2-4x+3=0
Factor:
(x-3)(x-1)=0
Solve for x:
x=3 y=13
x=1 y=5
Make sense?
RJ
www.math-unlock.com