SOLUTION: a boy has twice as many nickels as dimes and 5 more half dollars than nickels. if the total value of the coins is 6.10 how many half dollars does he have

Algebra ->  Problems-with-consecutive-odd-even-integers -> SOLUTION: a boy has twice as many nickels as dimes and 5 more half dollars than nickels. if the total value of the coins is 6.10 how many half dollars does he have      Log On


   



Question 496164: a boy has twice as many nickels as dimes and 5 more half dollars than nickels. if the total value of the coins is 6.10 how many half dollars does he have
Answer by jorel1380(3719) About Me  (Show Source):
You can put this solution on YOUR website!
5n+10(n/2)+50(n+5)=610
10n+50n+250=610
60n=360
n=6
The boy has 6 nickels, 3 dimes, and 11 half-dollars..