SOLUTION: the length of rectangle is 3 times its width. if the length is increased by 2 inches and the width by 1 inch, the new perimeter is 62 inches. What is the width before the increase

Algebra ->  Problems-with-consecutive-odd-even-integers -> SOLUTION: the length of rectangle is 3 times its width. if the length is increased by 2 inches and the width by 1 inch, the new perimeter is 62 inches. What is the width before the increase      Log On


   

Question 496097: the length of rectangle is 3 times its width. if the length is increased by 2 inches and the width by 1 inch, the new perimeter is 62 inches. What is the width before the increase
Answer by chessace(471) About Me  (Show Source):
You can put this solution on YOUR website!
L=3W
2(L+2)+2(W+1)=62
2L+2W=56
L+W=28
4W=28
W=7inches