SOLUTION: solve for x and y ; if x>0 and y>0 : log xy=log x/y + 2 log 2= 2

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Question 496065: solve for x and y ; if x>0 and y>0 : log xy=log x/y + 2 log 2= 2
Answer by chessace(471) About Me  (Show Source):
You can put this solution on YOUR website!
log x + log y = 2
log x - log y + 2 log 2 = 2
2 log y - 2 log 2 = 0
y = 2
log 2x = 2
2x = 100
x = 50