SOLUTION: the sum of three integers is one hundred twenty-three. The second number is two more than twice the first number. The third number is five less than the product of three and the
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Question 495508: the sum of three integers is one hundred twenty-three. The second number is two more than twice the first number. The third number is five less than the product of three and the first number. Find the three numbers. Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! Three integers, a, b, c
:
the sum of three integers is one hundred twenty-three.
a + b + c = 123
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The second number is two more than twice the first number.
b = 2a + 2
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The third number is five less than the product of three and the first number.
c = 3a - 5
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Replace b and c in the 1st equation, find a
a + (2a+2) + (3a-5) = 123
Combine like terms
6a - 3 = 123
6a = 123 + 3
6a = 126
a =
a = 21
:
I'll let you find b and c, check by finding the sum of all three values
