SOLUTION: Square root of (2x-3) + x = 3

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Question 4953: Square root of (2x-3) + x = 3
Found 2 solutions by Abbey, Earlsdon:
Answer by Abbey(339) About Me  (Show Source):
You can put this solution on YOUR website!
sqrt%282x-3%29%2Bx=3
Subtract x from both sides and rewrite this equation as
sqrt%282x-3%29=3-x
square both sides:
%28sqrt%282x-3%29%29%5E2=%283-x%29%5E2
2x-3=9-6x%2Bx%5E2
subtract 2x and add 3 to both sides to get
0=x%5E2-8x%2B12
Factor:
(x-6)(x-2)=0
x=6,2

Answer by Earlsdon(6294) About Me  (Show Source):
You can put this solution on YOUR website!
Solve:
sqrt%282x-3%29+x=3 Subtract x from both sides.
sqrt%282x-3%29=3-x Square both sides.
2x-3 = 9-6x+x^2 Simplify.
x^2-8x+12 = 0 Solve by factoring.
(x-2)(x-6) = 0 Apply the zero poducts principle.
x-2 = 0; x = 2
x-6 = 0; x = 6
The roots are: x = 2, x = 6