SOLUTION: factor completely 4c^2-4cd+d^2-9
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Question 49524
:
factor completely
4c^2-4cd+d^2-9
Answer by
stanbon(75887)
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4c^2-4cd+d^2-9
Factor the 1st three terms to get:
(2c-d)^2-9
This is the form a^2-b^2 which factors as (a+b)(a-b),
as follows:
[2c-d-3][2c-d+3]
Cheers,
Stan H.