SOLUTION: Two cars travel toward each other at constant velocities. One is going 12 m/s, and the other 18 m/s. They are 3000m apart when we first see them.
I need to get all the informa
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Question 495141: Two cars travel toward each other at constant velocities. One is going 12 m/s, and the other 18 m/s. They are 3000m apart when we first see them.
I need to get all the information I can out of this problem. There is no question. I want to know where they with either run into or pass each other? And anything else this information can tell me. Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! Two cars travel toward each other at constant velocities. One is going 12 m/s, and the other 18 m/s. They are 3000m apart when we first see them.
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Their closing rate is (10+18)m/s = 28 m/s
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time = distance/rate
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time = 3000m/28 = 107.17 seconds
The trains will meet in 107.17 sec
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Cheers,
Stan H.
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