Question 495115: 2. Determine whether the relation {(–2, 3), (–5, 6), (3, 0), (1, 1)} is a function
3. Delete one ordered pair so that the relation {(–4, 2), (1, 6), (0, 0), (–4, 6)} is a function.
Find ƒ(–5) for each function.
5. ƒ(x) = 5x + 35
6. ƒ(x) = x² – x
Answer by Edwin McCravy(20056) (Show Source):
You can put this solution on YOUR website! 2. Determine whether the relation {(–2, 3), (–5, 6), (3, 0), (1, 1)} is a function
We look at the first coordinates -2, -5, 3, and 1. None of those are
the same, so it is function.
3. Delete one ordered pair so that the relation {(–4, 2), (1, 6), (0, 0), (–4, 6)} is a function.
We look at the first coordinates -4, 1, 0, and -4. Two of those are
the same -4, so it is NOT a function. To make it into a function we can
delete either (-4, 2) or (-4, 6). You can put either of these as the
solution:
{(1, 6), (0, 0), (–4, 6)} or {(–4, 2), (1, 6), (0, 0)}
Find ƒ(–5) for each function.
5. ƒ(x) = 5x + 35
Everywhere you see an x, replace it by (-5)
ƒ(-5) = 5(-5) + 35
Then simplify the right side:
ƒ(-5) = -25 + 35
ƒ(-5) = 10
6. ƒ(x) = x² – x
Everywhere you see an x, replace it by (-5)
ƒ(-5) = (-5)² - (-5)
Then simplify the right side:
ƒ(-5) = 25 + 5
ƒ(-5) = 30
Edwin
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