SOLUTION: ) A bag contains 4 white and 5 black balls. One ball is drawn from the bag and is not replaced, when the second ball is drawn. Find the probability that both balls of the drawing a
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-> SOLUTION: ) A bag contains 4 white and 5 black balls. One ball is drawn from the bag and is not replaced, when the second ball is drawn. Find the probability that both balls of the drawing a
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Question 494820: ) A bag contains 4 white and 5 black balls. One ball is drawn from the bag and is not replaced, when the second ball is drawn. Find the probability that both balls of the drawing are white. Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! A bag contains 4 white and 5 black balls. One ball is drawn from the bag and is not replaced, when the second ball is drawn. Find the probability that both balls of the drawing are white.
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P(white AND white) = P(white)*P(white|white) = (4/9)*(3/8) = 1/6
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Cheers,
Stan H.
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