SOLUTION: {{{ (a - 1) (a + 2) (a - 3) = a^3 - 2a^2 - 5a + 6 }}} But how do i get that answer? Thanks

Algebra ->  Distributive-associative-commutative-properties -> SOLUTION: {{{ (a - 1) (a + 2) (a - 3) = a^3 - 2a^2 - 5a + 6 }}} But how do i get that answer? Thanks      Log On


   

Question 49445: +%28a+-+1%29+%28a+%2B+2%29+%28a+-+3%29+=+a%5E3+-+2a%5E2+-+5a+%2B+6+
But how do i get that answer?
Thanks
Answer by venugopalramana(3286) About Me  (Show Source):
You can put this solution on YOUR website!
+%28a+-+1%29+%28a+%2B+2%29+%28a+-+3%29+=+a%5E3+-+2a%5E2+-+5a+%2B+6+
But how do i get that answer?
Thanks
use formula (a+x)(a+y)(a+z)=a^3+a^2(x+y+z)+a(xy+yz+zx)+xyz..or multiply normally...using formula
a^3+a^2(-1+2-3)+a(-1*2-1*-3-3*2)+(-1)(3)(-2)
=a^3-2a^2-5a+6