SOLUTION: Can help me you solve
{{{ (1/sqrt32)^(-2/5)}}}
I switched to denominator and the numerator to get rid of the negative in the exponent. Then I am left with
{{{ sqrt32^(2/5
Algebra ->
Exponents-negative-and-fractional
-> SOLUTION: Can help me you solve
{{{ (1/sqrt32)^(-2/5)}}}
I switched to denominator and the numerator to get rid of the negative in the exponent. Then I am left with
{{{ sqrt32^(2/5
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Question 494315: Can help me you solve
I switched to denominator and the numerator to get rid of the negative in the exponent. Then I am left with
Next where do I go, if what I have done is right so far? Answer by chessace(471) (Show Source):
You can put this solution on YOUR website! Right so far!
sqrt(x) = x^1/2 which will cancel with the 2 part of the exponent,
leaving 32^(1/5). But 2^5 = 32, so the 5's cancel as well.
Ans = 2
