SOLUTION: I would like to compare two phone plans from verizon using a graph of a system of linear equations. Plan A includes 450 minutes for $40.00 per month plus a charge of .45 per minute
Question 493544: I would like to compare two phone plans from verizon using a graph of a system of linear equations. Plan A includes 450 minutes for $40.00 per month plus a charge of .45 per minute over 450. Plan B includes 900 minutes for $60.00 per month plus a charge of .40 per minute over 900. Solve for a user who averages 1250 minutes per month. Is there a solution set where the points merge? Thanks for taking a look :) Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! Plan A includes 450 minutes for $40.00 per month plus a charge of .45 per minute over 450.
Plan B includes 900 minutes for $60.00 per month plus a charge of .40 per minute over 900.
Solve for a user who averages 1250 minutes per month.
Plan A
C = .45(1250-450) + 40
C = .45(800) + 40
C = 360 + 40
C = $400
Plan B
C = .40(1250-900) + 60
C = .40(350) + 60
C = 140 + 60
C = $200
:
Is there a solution set where the points merge?
This would occur when Plan A cost = $60, The minutes would be < 900 so the 2nd plan will equal $60
:
.45(m-450) + 40 = 60
.45m - 202.5 = 60 - 40
.45m - 202.5 = 20
.45m = 20 + 202.5
.45m = 222.5
m =
m ~ 494 minutes Plan A is very close to the same cost as Plan B
(the 1st 450 min cost only $40. the next 44 min; .45(44) = $19.80 for a total of $58.80
:
You can see that at 495 minutes, Plan A would be slightly more, and continue to be more thereafter.
:
C = .45(495 - 450) + 40
C = .45(45) + 40
C = 20.25 + 40
C = $60.25
:
Note that plan B remains at $60 all the way up to 900 minutes
:
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Did this make sense to you?
