SOLUTION: Jill has $3.50 in nickles and dimes. If she has 50 coins, how many of each type of coin does she have?

Algebra ->  Coordinate Systems and Linear Equations  -> Linear Equations and Systems Word Problems -> SOLUTION: Jill has $3.50 in nickles and dimes. If she has 50 coins, how many of each type of coin does she have?      Log On


   

Question 49354This question is from textbook Beginning Algebra
: Jill has $3.50 in nickles and dimes. If she has 50 coins, how many of each type of coin does she have? This question is from textbook Beginning Algebra

Answer by Nate(3500) About Me  (Show Source):
You can put this solution on YOUR website!
amount of nickels = n
amount of dimes = d
d+%2B+n+=+50 which can mean: n+=+50+-+d
0.1d+%2B+0.05n+=+3.5
plug:
0.1d+%2B+0.05%2850+-+d%29+=+3.5
0.1d+%2B+2.5+-+0.05d+=+3.5
0.05d+=+1
d+=+20
plug:
n+=+50+-+d
n+=+50+-+20+=+30
20 dimes and 30 nickels