SOLUTION: hi . the question that i have given to you is wrong . here is the new . please help to solve this because i need it tomorrow . tank you :) {{{ 4/w+3w/(w^2-4)-(2w+1)/(w^2-4w+4)

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: hi . the question that i have given to you is wrong . here is the new . please help to solve this because i need it tomorrow . tank you :) {{{ 4/w+3w/(w^2-4)-(2w+1)/(w^2-4w+4)       Log On


   

Question 492723: hi . the question that i have given to you is wrong . here is the new .
please help to solve this because i need it tomorrow . tank you :)
+4%2Fw%2B3w%2F%28w%5E2-4%29-%282w%2B1%29%2F%28w%5E2-4w%2B4%29+
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
[4/w] + [3w/(w^2-4)] - [(2w+1)/(w^2-4w+4)]
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lcd = w(w+2)(w-2)^2
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Rewrite each fraction with the lcd as its denominator:
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= [4(w+2)(w-2)^2/lcd] + [3w*w(w-2)/lcd] - [(2w+1)w(w+2)/lcd]
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Combine the numerators over the lcd:
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= [4(w+2)(w-2)^2 + 3w*w(w-2) - (2w+1)w(w+2)] / lcd
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I'll leave the rest to you.
Cheers,
Stan H.