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Question 49265: slove the equation
5d+17=4(d+3)
-4(n+2=3(n-4)
7(t-3)=2(t-9)+2t
3(2x-5)-x=-7(x+3)
its this correct 1/5x+1/2=1
10(1/5x+1/2)=1
2x+5=1
x=-2
Answer by TheAntiheroX9(4) (Show Source):
You can put this solution on YOUR website! 5d+17=4(d+3) (multiply 4 by d and 3)
5d + 17 = 4d + 12
5d + 17 = 4d + 12
-12 -12 (subtract 12 from both sides)
5d +5 = 4d
-4d -4d (subtract 4d from both sides)
d +5= 0
-5 -5 (isolate the d so you subtract 5 from both sides)
d= - 5
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-4(n+2=3(n-4) (multiply the -4 by the n and the 2 & the 3 by the n and -4)
-4n - 8 = 3n - 12
-4n - 8 = 3n - 12
+ 12 + 12 (add the lesser number {-12} to both sides)
-4n + 4 = 3n
+4n +4n (add the lessen n value (-4n) to both sides)
4= 7n
4/7= 7n/7 (divide 7n by 7 and 4 by 7)
4/7= n
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7(t-3)=2(t-9)+2t (multiply the 7 by the t and -3 & the 2 by the t and -9)
7t - 21 = 2t -18 + 2t
7t - 21= 4t -18 (combine like terms)
7t - 21= 4t -18
+ 21 +21 (add the lesser number (-21) to both sides)
7t = 4t + 3
-4t -4t (subtrace the lesser T value (4t) from both sides)
3t= 3
3t / 3= 3/ 3 (divide 3t and 3 by 3)
t= 1
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3(2x-5)-x=-7(x+3)
6x - 15 - x = -7x - 21
5x - 15= -7x -21 (combine like terms)
5x - 15= -7x -21
+21 +21 (add the lesser value (-21) to both sides)
5x + 6= -7x
+7x +7x (add the lesser x value (-7x) to both sides to cancle it out)
12x +6= 0
-6 -6 (subtract 6 from both to isolate the 12x)
12x= -6
12x / 12= -6 /12 (divide by 12)
x= -6/12 (simplify)
x= -1/2
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This problem was correct how you did it.
10(1/5x+1/2)=1 (multiply)
2x + 5= 1
2x + 5= 1
- 5 -5 (subtract the 5)
2x= -4
2x /2= -4 /2 (divide by 2)
x= -2
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