SOLUTION: What quantity of 80 per cent acid solution must be mixed with a 25 percent solution to produce 660 mL of a 50 per cent solution?

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Question 492615: What quantity of 80 per cent acid solution must be mixed with a 25 percent solution to produce 660 mL of a 50 per cent solution?
Answer by mananth(16946) About Me  (Show Source):
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percent percentage ---------------- quantity
Acid I 80 ---------------- x ml
Acid II 25 ---------------- 660 - x ml
Mixture 50.00% ---------------- 660

80 x + 25 ( 660 - x ) = 50 * 660

80 x + 16500 - 25 x = 33000
80 x - 25 x = 33000 - 16500
55 x = 16500
/ 55
x= 300 ml 80.00% Acid I
360 ml 25.00% Acid II