SOLUTION: Ebony has 4 male and 7 female kittens. She picks up 2 kittens to give to a friend. Find the probability of each selection.
P(2 male)
P (2 female)
P (1 of each)
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-> SOLUTION: Ebony has 4 male and 7 female kittens. She picks up 2 kittens to give to a friend. Find the probability of each selection.
P(2 male)
P (2 female)
P (1 of each)
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Question 492609: Ebony has 4 male and 7 female kittens. She picks up 2 kittens to give to a friend. Find the probability of each selection.
P(2 male)
P (2 female)
P (1 of each) Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! Ebony has 4 male and 7 female kittens. She picks up 2 kittens to give to a friend. Find the probability of each selection.
P(2 male) = 4C2/11C2 = 6/55
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P (2 female) = 7C2/11C2 = 21/55
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P (1 of each) = 1 - [6/55 + 21/55] = 1 - [27/55] = 28/55
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Cheers,
Stan H.
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