SOLUTION: a square and a rectangle have the same area. the length of the rectangle is 8 more than s side of the square, and the width of the rectangle is 4 less than a side of the square. fi

Algebra ->  Length-and-distance -> SOLUTION: a square and a rectangle have the same area. the length of the rectangle is 8 more than s side of the square, and the width of the rectangle is 4 less than a side of the square. fi      Log On


   

Question 492498: a square and a rectangle have the same area. the length of the rectangle is 8 more than s side of the square, and the width of the rectangle is 4 less than a side of the square. find a side of the square.
Answer by WhuddaPeach(6) About Me  (Show Source):
You can put this solution on YOUR website!
Basically, this tells us that
s%2As+=+%28s%2B8%29%28s-4%29
s is the length of the square's side. So, the area of the square is s^2, and the area of the rectangle is (s+8)(s-4)
Simplify.
s%5E2+=+s%5E2%2B4s-32
The s^2 cancel out.
0+=+4s-32
Add 32 to both sides.
32+=+4s
Divide by 4.
8+=+s