SOLUTION: At 9:00 A.M. your friends begin a hike, walking at 3 mi/h. Starting late, you begin from the same place at 9:45 A.M. If you run at 8 mi/h, when will you catch your friends?

Algebra ->  Customizable Word Problem Solvers  -> Travel -> SOLUTION: At 9:00 A.M. your friends begin a hike, walking at 3 mi/h. Starting late, you begin from the same place at 9:45 A.M. If you run at 8 mi/h, when will you catch your friends?      Log On

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Question 49239: At 9:00 A.M. your friends begin a hike, walking at 3 mi/h. Starting late, you begin from the same place at 9:45 A.M. If you run at 8 mi/h, when will you catch your friends?
Answer by Nate(3500) About Me  (Show Source):
You can put this solution on YOUR website!
45 minutes already past ~> 45/60 = 3/4 of an hour ~> (3/4)*3 = 9/4 = 2.25 miles already past by the walker
f(x) = 3x + 2.25 for the walker
f(x) = 8x for the runner
When the equations are equal, they will meet at that time.
3x + 2.25 = 8x
2.25 = 5x
9/20 = x
(9/20)(60) = 27 minutes until they meet
10:12 A.M.