SOLUTION: How do you solve the following problem: If 90degrees < 0 < 180degrees and sin 0 = 10/26, then cos 0 =

Algebra ->  Trigonometry-basics -> SOLUTION: How do you solve the following problem: If 90degrees < 0 < 180degrees and sin 0 = 10/26, then cos 0 =      Log On


   

Question 492328: How do you solve the following problem:
If 90degrees < 0 < 180degrees and sin 0 = 10/26, then cos 0 =
Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
How do you solve the following problem:
If 90degrees < 0 < 180degrees and sin 0 = 10/26, then cos 0
**
sim x=10/26
This means you are working with a right triangle in quadrant II where sin is >0 and cos<0.
hypotenuse=26
opposite side=10
adjacent side=√(26^2-10^2)=√576=24
cos x=-24/26