SOLUTION: By using the even-odd properties to find the exact value of each expression.
sin(-135(degrees))
sec(-pi)
tan( (-pi) / (3) )
I apologize for three questions but they are
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-> SOLUTION: By using the even-odd properties to find the exact value of each expression.
sin(-135(degrees))
sec(-pi)
tan( (-pi) / (3) )
I apologize for three questions but they are
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Question 492294: By using the even-odd properties to find the exact value of each expression.
sin(-135(degrees))
sec(-pi)
tan( (-pi) / (3) )
I apologize for three questions but they are all related. Answer by lwsshak3(11628) (Show Source):
You can put this solution on YOUR website! By using the even-odd properties to find the exact value of each expression.
sin(-135(degrees))
sec(-pi)
tan( (-pi) / (3) )
I apologize for three questions but they are all related.
**
Even function: f(-x)=f(x)
Odd function: f(-x)=-f(x)
..
sin is an odd function
135º is in quadrant II where the reference angle=45º
Sin 135º=√2/2
Sin (-135º)=-√2/2
..
sec is an even function
sec π=1/cos π=1/-1=-1
sec(-π)=-1
..
tan is an odd function
π/3=60º in quadrant I
tan π/3=√3
tan -π/3=-√3
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