Question 492287: How would I find the exact value of
sin (6pi) ?
and
cos (-11pi/2) ?
Thank you
Answer by lwsshak3(11628)   (Show Source):
You can put this solution on YOUR website! How would I find the exact value of
sin (6pi) ?
and
cos (-11pi/2) ?
**
sin 6π
Starting from zero, this means rotating thru π or180º 6 times counter-clockwise which ends at zero.
So, sin 6π=0
..
cos (-11pi/2)
This means rotating thru π/2 or 90º 11 times in the clockwise direction. After 8 times you will be at zero, and 3 more times clockwise puts you at π/2 or 90º
So, cos(-11π/2)=0
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