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Here is the question:
Let ( (-2/sqrt(5)), (1/sqrt(5)) ) be the point on the unit circle that corresponds to a real number, t. Find the exact values of
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Here is the question:
Let ( (-2/sqrt(5)), (1/sqrt(5)) ) be the point on the unit circle that corresponds to a real number, t. Find the exact values of
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Question 492285: Thank you for your time
Here is the question:
Let ( (-2/sqrt(5)), (1/sqrt(5)) ) be the point on the unit circle that corresponds to a real number, t. Find the exact values of the six trigonometric functions of t. Answer by lwsshak3(11628) (Show Source):
You can put this solution on YOUR website! Let ( (-2/sqrt(5)), (1/sqrt(5)) ) be the point on the unit circle that corresponds to a real number, t. Find the exact values of the six trigonometric functions of t
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You are working with a right triangle in quadrant II where sin>0 and cos<0.
Opposite side=1/√5
Adjacent side=-2√5
Hypotenuse=√[(1/√5)^2+(2/√5)^2]=√[(1/5)+(4/5)]=√1=1
..
Trig functions:
sin t=(1/√5)/1=1/√5
cos t=(-2√5)/1=-2/√5=-2√5/5
tan t=sin t/cos t=(1/√5)/(-2√5)= -1/2
csc t=1/sin t=√5
sec t=1/cos t=-√5/2
cot t=1/tan t=-2
(