SOLUTION: QS bisects ∠PQR, m∠PQR = (4x + 2) °, and m∠SQR = (3x - 6) °. What is the value of x?

Algebra ->  Formulas -> SOLUTION: QS bisects ∠PQR, m∠PQR = (4x + 2) °, and m∠SQR = (3x - 6) °. What is the value of x?      Log On


   

Question 492128: QS bisects ∠PQR, m∠PQR = (4x + 2) °, and
m∠SQR = (3x - 6) °. What is the value of x?
Answer by cleomenius(959) About Me  (Show Source):
You can put this solution on YOUR website!
Since QS bisects angle PQR, SQR is 1/2 of PQR.
2(3x - 6) = (4x + 2)
6x -12 = 4x + 2
2x = 14.
x = 7
SQR = (7)(3) - 6 = 15
PQR = 4(7) + 2 = 30
This does check.
cleomenius.