SOLUTION: Please help me with this...I can not figure this out.
Science and medicine: The equation h= -16t^2 +112t gives the height of an arrow, shot upward from the ground with and init
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Science and medicine: The equation h= -16t^2 +112t gives the height of an arrow, shot upward from the ground with and init
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Question 49206: Please help me with this...I can not figure this out.
Science and medicine: The equation h= -16t^2 +112t gives the height of an arrow, shot upward from the ground with and initial velocity of 112 ft/s, where t is the time after the arrow leaves the ground. Find the time it takes for the arrow to reach height of 180 ft. Answer by tutorcecilia(2152) (Show Source):
You can put this solution on YOUR website! h= -16t^2 +112t
180=-16t^2 +112t
180-180 = -16t^2 +112t -180
-16t^2 +112t -180 = 0
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t = 2.5 or t = 4.5
