SOLUTION: Can someone walk through with me? A ball is thrown vertically downward from the top of a 36.6 m tall building. the ball passes the top of a window that is 12.2 m above the groun

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Question 491861: Can someone walk through with me?
A ball is thrown vertically downward from the top of a 36.6 m tall building. the ball passes the top of a window that is 12.2 m above the ground 2.00 seconda after being thrown. What is the speed of the ball as it passes the top of the window?
Thank you,
Answer by scott8148(6628) About Me  (Show Source):
You can put this solution on YOUR website!
the ball traveled 24.4 m (36.6 - 12.2) in 2 sec for an average velocity of 12.2 m/s

the velocity at the window is the initial velocity PLUS 2 seconds of gravitational acceleration
___ Vf = Vi + 2(9.8) ___ Vf - 19.6 = Vi

Vave = (Vf + Vi) / 2

substituting ___ 12.2 = [Vf + (Vf - 19.6)] / 2 ___ 24.4 = 2 Vf - 19.6 ___ 22.0 = Vf