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Question 491814: i am a 3 digit number divisible by 3.my tens digit is 3 times as great as my hundreds digit and the sum of my digits is 15. if you reverse my digits i am divisible by 6 and 3...... what number am i?
Answer by ankor@dixie-net.com(22740)   (Show Source):
You can put this solution on YOUR website! i am a 3 digit number divisible by 3.
100a + 10b + c
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my tens digit is 3 times as great as my hundreds digit
b = 3a, from this we know a = 1, 2, 3, then b = 3, 6, 9
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and the sum of my digits is 15.
a + b + c = 15
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if you reverse my digits i am divisible by 6 and 3
100c + 10b + a
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this is a logic problem, an equation won't help us here
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From the given information b = 3a, and the sum of the 3 digits = 15, we have:
1 3 ___; three single digits can't add up to 15
2 6 _7_; this has to be the number
3 9 _3_; reverse number is not different
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Check for division by 3 and 6
267/3 = 89
762/6 = 127
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267 is the number
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