SOLUTION: Find the value of k for which the graph of 6x-ky= 2 is perpendicular to 2x+3y= 7

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Question 491676: Find the value of k for which the graph of 6x-ky= 2 is perpendicular to 2x+3y= 7
Answer by oberobic(2304) About Me  (Show Source):
You can put this solution on YOUR website!
2x + 3y = 7
3y = -2x +7
y = -2/3*x +7/3
.
So the slope of the perpendicular line is the inverse reciprocal: 3/2.
.
6x -ky = 7
-ky = -6x +7
The value of k must be picked to make the slope = 3/2.
So k=4 results in
y = 3/2x + 7/4
.
Graph
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