SOLUTION: A federal report stated that 88% of children under age 18 were covered by health insurance in 2000. How large a sample is needed to estimate the true proportion of covered chil

Algebra ->  Probability-and-statistics -> SOLUTION: A federal report stated that 88% of children under age 18 were covered by health insurance in 2000. How large a sample is needed to estimate the true proportion of covered chil      Log On


   



Question 491599: A federal
report stated that 88% of children under age 18 were
covered by health insurance in 2000. How large a
sample is needed to estimate the true proportion of
covered children with 90% confidence with a
confidence interval 0.05 wide?

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
A federal
report stated that 88% of children under age 18 were
covered by health insurance in 2000. How large a
sample is needed to estimate the true proportion of
covered children with 90% confidence with a
confidence interval 0.05 wide?
--------
If the CI is 0.05 wide
2E = 0.05
E = 0.025
---
Since E = z*sqrt(pq/n)
sqrt(n) = [z/E]*sqrt(pq)
---
So, n = [z/E]^2*pq
----
n = [1.645/0.025]^2*0.18*0.72
---
n = 562 when rounded up
============================
Cheers,
Stan H.